Type.parse Method
Returns an instance of the type specified by a type name. This is a static member that is invoked directly without creating an instance of its class.
Syntax
var typeVar = Type.parse(typeName, ns);
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typeName
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A string that represents a fully qualified class name. Can be null.
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ns
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(Optional) The namespace that contains the class.
Return Value
The class represented by typeName, or null if a class that matches typeName does not occur in the namespace.
Exceptions
| Exception Type |
Condition |
|
argument Function
|
(Debug) typeName cannot be evaluated as a class.
|
Remarks
Use the parse method to get an instance of a class represented by a specified class-name string. If the namespace is not provided, the class name specified in typeName must be a fully qualified class name that consists of a namespace specification and a class name. If the namespace is provided, a class matching typeName in the specified namespace is returned.